Base | Representation |
---|---|
bin | 11101001110010010100… |
… | …10101111001110010111 |
3 | 10112222202202210021000002 |
4 | 32213021102233032113 |
5 | 112422401223344112 |
6 | 2045140152241515 |
7 | 132354434350343 |
oct | 16471122571627 |
9 | 3488682707002 |
10 | 1004104512407 |
11 | 357924902907 |
12 | 1427286a029b |
13 | 738c07508c9 |
14 | 36855604623 |
15 | 1b1bbc831c2 |
hex | e9c94af397 |
1004104512407 has 2 divisors, whose sum is σ = 1004104512408. Its totient is φ = 1004104512406.
The previous prime is 1004104512373. The next prime is 1004104512419. The reversal of 1004104512407 is 7042154014001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1004104512407 - 212 = 1004104508311 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1004104512407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1004104512487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502052256203 + 502052256204.
It is an arithmetic number, because the mean of its divisors is an integer number (502052256204).
Almost surely, 21004104512407 is an apocalyptic number.
1004104512407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004104512407 is an equidigital number, since it uses as much as digits as its factorization.
1004104512407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4480, while the sum is 29.
Adding to 1004104512407 its reverse (7042154014001), we get a palindrome (8046258526408).
The spelling of 1004104512407 in words is "one trillion, four billion, one hundred four million, five hundred twelve thousand, four hundred seven".
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