Base | Representation |
---|---|
bin | 111011110110110… |
… | …011011111011111 |
3 | 2120222121210012101 |
4 | 323312303133133 |
5 | 4024040104211 |
6 | 243351545531 |
7 | 33612515122 |
oct | 7366633737 |
9 | 2528553171 |
10 | 1004222431 |
11 | 4759481a3 |
12 | 24038b2a7 |
13 | 130088074 |
14 | 9752a3b9 |
15 | 5d2675c1 |
hex | 3bdb37df |
1004222431 has 4 divisors (see below), whose sum is σ = 1004807664. Its totient is φ = 1003637200.
The previous prime is 1004222423. The next prime is 1004222441. The reversal of 1004222431 is 1342224001.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1342224001 = 17 ⋅78954353.
It is a cyclic number.
It is not a de Polignac number, because 1004222431 - 23 = 1004222423 is a prime.
It is a super-2 number, since 2×10042224312 = 2016925381847099522, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1004222399 and 1004222408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1004222441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 290035 + ... + 293476.
It is an arithmetic number, because the mean of its divisors is an integer number (251201916).
Almost surely, 21004222431 is an apocalyptic number.
1004222431 is a deficient number, since it is larger than the sum of its proper divisors (585233).
1004222431 is an equidigital number, since it uses as much as digits as its factorization.
1004222431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 585232.
The product of its (nonzero) digits is 384, while the sum is 19.
The square root of 1004222431 is about 31689.4687711864. The cubic root of 1004222431 is about 1001.4055006425.
Adding to 1004222431 its reverse (1342224001), we get a palindrome (2346446432).
It can be divided in two parts, 1004222 and 431, that added together give a triangular number (1004653 = T1417).
The spelling of 1004222431 in words is "one billion, four million, two hundred twenty-two thousand, four hundred thirty-one".
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