Base | Representation |
---|---|
bin | 1001001000101000111001… |
… | …0011111100001100110011 |
3 | 1022120012101002202100201220 |
4 | 2102022032103330030303 |
5 | 2304030123402130120 |
6 | 33210054250400123 |
7 | 2054441130645264 |
oct | 222121623741463 |
9 | 38505332670656 |
10 | 10044021130035 |
11 | 3222711098622 |
12 | 1162722430043 |
13 | 57b1bb31a069 |
14 | 26a1c179096b |
15 | 126404975b40 |
hex | 9228e4fc333 |
10044021130035 has 64 divisors (see below), whose sum is σ = 17429756940288. Its totient is φ = 4919283339264.
The previous prime is 10044021130027. The next prime is 10044021130049. The reversal of 10044021130035 is 53003112044001.
It is a happy number.
It is not a de Polignac number, because 10044021130035 - 23 = 10044021130027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10044021129987 and 10044021130014.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9969054 + ... + 10930236.
It is an arithmetic number, because the mean of its divisors is an integer number (272339952192).
Almost surely, 210044021130035 is an apocalyptic number.
10044021130035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10044021130035 is a deficient number, since it is larger than the sum of its proper divisors (7385735810253).
10044021130035 is a wasteful number, since it uses less digits than its factorization.
10044021130035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 962204.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 10044021130035 its reverse (53003112044001), we get a palindrome (63047133174036).
The spelling of 10044021130035 in words is "ten trillion, forty-four billion, twenty-one million, one hundred thirty thousand, thirty-five".
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