10053400117 has 2 divisors, whose sum is σ = 10053400118. Its totient is φ = 10053400116.

The previous prime is 10053400081. The next prime is 10053400153. The reversal of 10053400117 is 71100435001.

It is a balanced prime because it is at equal distance from previous prime (10053400081) and next prime (10053400153).

It can be written as a sum of positive squares in only one way, i.e., 8047166436 + 2006233681 = 89706^2 + 44791^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10053400117 is a prime.

It is a super-2 number, since 2×10053400117² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10053401117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5026700058 + 5026700059.

It is an arithmetic number, because the mean of its divisors is an integer number (5026700059).

Almost surely, 2^10053400117 is an apocalyptic number.

It is an amenable number.

10053400117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10053400117 is an equidigital number, since it uses as much as digits as its factorization.

10053400117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 420, while the sum is 22.

Adding to 10053400117 its reverse (71100435001), we get a palindrome (81153835118).

The spelling of 10053400117 in words is "ten billion, fifty-three million, four hundred thousand, one hundred seventeen".