10053401117 has 2 divisors, whose sum is σ = 10053401118. Its totient is φ = 10053401116.

The previous prime is 10053401093. The next prime is 10053401123. The reversal of 10053401117 is 71110435001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7824994681 + 2228406436 = 88459^2 + 47206^2 .

It is an emirp because it is prime and its reverse (71110435001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10053401117 - 2²² = 10049206813 is a prime.

It is a super-3 number, since 3×10053401117³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10053401092 and 10053401101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10053401317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5026700558 + 5026700559.

It is an arithmetic number, because the mean of its divisors is an integer number (5026700559).

Almost surely, 2^10053401117 is an apocalyptic number.

It is an amenable number.

10053401117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10053401117 is an equidigital number, since it uses as much as digits as its factorization.

10053401117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 420, while the sum is 23.

Adding to 10053401117 its reverse (71110435001), we get a palindrome (81163836118).

The spelling of 10053401117 in words is "ten billion, fifty-three million, four hundred one thousand, one hundred seventeen".