Base | Representation |
---|---|
bin | 1001001011111001011011… |
… | …1010011011001101111101 |
3 | 1022202112212100220011100102 |
4 | 2102332112322123031331 |
5 | 2310434300000324013 |
6 | 33251513112210445 |
7 | 2061462262410254 |
oct | 222762672331575 |
9 | 38675770804312 |
10 | 10100000011133 |
11 | 324442777751a |
12 | 1171545699a25 |
13 | 58356c970046 |
14 | 26cbb219379b |
15 | 127ace180d58 |
hex | 92f96e9b37d |
10100000011133 has 2 divisors, whose sum is σ = 10100000011134. Its totient is φ = 10100000011132.
The previous prime is 10100000011111. The next prime is 10100000011273. The reversal of 10100000011133 is 33111000000101.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5223843938329 + 4876156072804 = 2285573^2 + 2208202^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10100000011133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10100000011433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050000005566 + 5050000005567.
It is an arithmetic number, because the mean of its divisors is an integer number (5050000005567).
Almost surely, 210100000011133 is an apocalyptic number.
It is an amenable number.
10100000011133 is a deficient number, since it is larger than the sum of its proper divisors (1).
10100000011133 is an equidigital number, since it uses as much as digits as its factorization.
10100000011133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9, while the sum is 11.
Adding to 10100000011133 its reverse (33111000000101), we get a palindrome (43211000011234).
The spelling of 10100000011133 in words is "ten trillion, one hundred billion, eleven thousand, one hundred thirty-three".
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