1010001133 has 2 divisors, whose sum is σ = 1010001134. Its totient is φ = 1010001132.

The previous prime is 1010001101. The next prime is 1010001143. The reversal of 1010001133 is 3311000101.

It is an a-pointer prime, because the next prime (1010001143) can be obtained adding 1010001133 to its sum of digits (10).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 805310884 + 204690249 = 28378^2 + 14307^2 .

It is a cyclic number.

It is not a de Polignac number, because 1010001133 - 2⁵ = 1010001101 is a prime.

It is a super-2 number, since 2×1010001133² = 2040204577322567378, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1010001143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505000566 + 505000567.

It is an arithmetic number, because the mean of its divisors is an integer number (505000567).

Almost surely, 2^1010001133 is an apocalyptic number.

It is an amenable number.

1010001133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010001133 is an equidigital number, since it uses as much as digits as its factorization.

1010001133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 10.

The square root of 1010001133 is about 31780.5149895341. The cubic root of 1010001133 is about 1003.3226587116.

Adding to 1010001133 its reverse (3311000101), we get a palindrome (4321001234).

The spelling of 1010001133 in words is "one billion, ten million, one thousand, one hundred thirty-three".