1010004711413 has 2 divisors, whose sum is σ = 1010004711414. Its totient is φ = 1010004711412.

The previous prime is 1010004711409. The next prime is 1010004711431. The reversal of 1010004711413 is 3141174000101.

Together with next prime (1010004711431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 678807914404 + 331196797009 = 823898^2 + 575497^2 .

It is a cyclic number.

It is not a de Polignac number, because 1010004711413 - 2² = 1010004711409 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1010004711113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505002355706 + 505002355707.

It is an arithmetic number, because the mean of its divisors is an integer number (505002355707).

Almost surely, 2^{1010004711413} is an apocalyptic number.

It is an amenable number.

1010004711413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010004711413 is an equidigital number, since it uses as much as digits as its factorization.

1010004711413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 23.

Adding to 1010004711413 its reverse (3141174000101), we get a palindrome (4151178711514).

The spelling of 1010004711413 in words is "one trillion, ten billion, four million, seven hundred eleven thousand, four hundred thirteen".