Base | Representation |
---|---|
bin | 10010110100000001… |
… | …10111101010010111 |
3 | 222001220010212000002 |
4 | 21122000313222113 |
5 | 131141112041043 |
6 | 4350120241515 |
7 | 505201351511 |
oct | 113200675227 |
9 | 28056125002 |
10 | 10100112023 |
11 | 4313282721 |
12 | 1b5a61029b |
13 | c4c66cc61 |
14 | 6bb582bb1 |
15 | 3e1a85bb8 |
hex | 25a037a97 |
10100112023 has 2 divisors, whose sum is σ = 10100112024. Its totient is φ = 10100112022.
The previous prime is 10100112013. The next prime is 10100112049. The reversal of 10100112023 is 32021100101.
10100112023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10100112023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10100111995 and 10100112013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10100112013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050056011 + 5050056012.
It is an arithmetic number, because the mean of its divisors is an integer number (5050056012).
Almost surely, 210100112023 is an apocalyptic number.
10100112023 is a deficient number, since it is larger than the sum of its proper divisors (1).
10100112023 is an equidigital number, since it uses as much as digits as its factorization.
10100112023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 10100112023 its reverse (32021100101), we get a palindrome (42121212124).
The spelling of 10100112023 in words is "ten billion, one hundred million, one hundred twelve thousand, twenty-three".
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