101001121100041 has 2 divisors, whose sum is σ = 101001121100042. Its totient is φ = 101001121100040.

The previous prime is 101001121100029. The next prime is 101001121100053. The reversal of 101001121100041 is 140001121100101.

It is a balanced prime because it is at equal distance from previous prime (101001121100029) and next prime (101001121100053).

It can be written as a sum of positive squares in only one way, i.e., 73944176846400 + 27056944253641 = 8599080^2 + 5201629^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101001121100041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101001121099994 and 101001121100030.

It is not a weakly prime, because it can be changed into another prime (101001121104041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500560550020 + 50500560550021.

It is an arithmetic number, because the mean of its divisors is an integer number (50500560550021).

Almost surely, 2^{101001121100041} is an apocalyptic number.

It is an amenable number.

101001121100041 is a deficient number, since it is larger than the sum of its proper divisors (1).

101001121100041 is an equidigital number, since it uses as much as digits as its factorization.

101001121100041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 101001121100041 its reverse (140001121100101), we get a palindrome (241002242200142).

The spelling of 101001121100041 in words is "one hundred one trillion, one billion, one hundred twenty-one million, one hundred thousand, forty-one".