101001122111 has 4 divisors (see below), whose sum is σ = 101037339000. Its totient is φ = 100964905224.

The previous prime is 101001121909. The next prime is 101001122149. The reversal of 101001122111 is 111221100101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111221100101 = 17 ⋅6542417653.

It is a cyclic number.

It is not a de Polignac number, because 101001122111 - 2³⁴ = 83821252927 is a prime.

It is a super-3 number, since 3×101001122111³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101001122092 and 101001122101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101001122171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18104261 + ... + 18109838.

It is an arithmetic number, because the mean of its divisors is an integer number (25259334750).

Almost surely, 2^101001122111 is an apocalyptic number.

101001122111 is a deficient number, since it is larger than the sum of its proper divisors (36216889).

101001122111 is an equidigital number, since it uses as much as digits as its factorization.

101001122111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36216888.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 101001122111 its reverse (111221100101), we get a palindrome (212222222212).

The spelling of 101001122111 in words is "one hundred one billion, one million, one hundred twenty-two thousand, one hundred eleven".