101002133111 has 4 divisors (see below), whose sum is σ = 110184145224. Its totient is φ = 91820121000.

The previous prime is 101002133077. The next prime is 101002133147. The reversal of 101002133111 is 111331200101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101002133111 - 2¹⁰ = 101002132087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101002136111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4591006040 + ... + 4591006061.

It is an arithmetic number, because the mean of its divisors is an integer number (27546036306).

Almost surely, 2^101002133111 is an apocalyptic number.

101002133111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

101002133111 is a deficient number, since it is larger than the sum of its proper divisors (9182012113).

101002133111 is an equidigital number, since it uses as much as digits as its factorization.

101002133111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9182012112.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 101002133111 its reverse (111331200101), we get a palindrome (212333333212).

The spelling of 101002133111 in words is "one hundred one billion, two million, one hundred thirty-three thousand, one hundred eleven".