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10100910000119 is a prime number
BaseRepresentation
bin1001001011111100110100…
…1001110000011111110111
31022202122012210012101120012
42102333031021300133313
52310443130430000434
633252143300330435
72061523652241341
oct222771511603767
938678183171505
1010100910000119
113244854401734
12117175a3a3a1b
13583686353273
1426cc5ad90291
15127b33ed23ce
hex92fcd2707f7

10100910000119 has 2 divisors, whose sum is σ = 10100910000120. Its totient is φ = 10100910000118.

The previous prime is 10100910000079. The next prime is 10100910000149. The reversal of 10100910000119 is 91100001900101.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (91100001900101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10100910000119 is a prime.

It is a super-2 number, since 2×101009100001192 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10100910000094 and 10100910000103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10100910000149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050455000059 + 5050455000060.

It is an arithmetic number, because the mean of its divisors is an integer number (5050455000060).

Almost surely, 210100910000119 is an apocalyptic number.

10100910000119 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100910000119 is an equidigital number, since it uses as much as digits as its factorization.

10100910000119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 23.

The spelling of 10100910000119 in words is "ten trillion, one hundred billion, nine hundred ten million, one hundred nineteen", and thus it is an aban number.