Base | Representation |
---|---|
bin | 10110111101111001000000… |
… | …011001100001100011111111 |
3 | 111020122110210000202021111222 |
4 | 112331321000121201203333 |
5 | 101214422212023101343 |
6 | 554455224211503555 |
7 | 30163511653421222 |
oct | 2675710031414377 |
9 | 436573700667458 |
10 | 101010121300223 |
11 | 2a2041741667a3 |
12 | b3b45312b7bbb |
13 | 44492a128c915 |
14 | 1ad2cb75555b9 |
15 | ba27898a4a68 |
hex | 5bde406618ff |
101010121300223 has 2 divisors, whose sum is σ = 101010121300224. Its totient is φ = 101010121300222.
The previous prime is 101010121300177. The next prime is 101010121300279. The reversal of 101010121300223 is 322003121010101.
It is a weak prime.
It is an emirp because it is prime and its reverse (322003121010101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101010121300223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101010121306223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505060650111 + 50505060650112.
It is an arithmetic number, because the mean of its divisors is an integer number (50505060650112).
Almost surely, 2101010121300223 is an apocalyptic number.
101010121300223 is a deficient number, since it is larger than the sum of its proper divisors (1).
101010121300223 is an equidigital number, since it uses as much as digits as its factorization.
101010121300223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 101010121300223 its reverse (322003121010101), we get a palindrome (423013242310324).
The spelling of 101010121300223 in words is "one hundred one trillion, ten billion, one hundred twenty-one million, three hundred thousand, two hundred twenty-three".
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