Base | Representation |
---|---|
bin | 1001001011111101100001… |
… | …1110100011001110010111 |
3 | 1022202122201000201101121102 |
4 | 2102333120132203032113 |
5 | 2310444023100001101 |
6 | 33252214204540315 |
7 | 2061531450226316 |
oct | 222773036431627 |
9 | 38678630641542 |
10 | 10101100000151 |
11 | 3244941684556 |
12 | 11717b1b5169b |
13 | 5836b6818a14 |
14 | 26cc782cc27d |
15 | 127b45a1386b |
hex | 92fd87a3397 |
10101100000151 has 2 divisors, whose sum is σ = 10101100000152. Its totient is φ = 10101100000150.
The previous prime is 10101100000067. The next prime is 10101100000153. The reversal of 10101100000151 is 15100000110101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10101100000151 - 218 = 10101099738007 is a prime.
Together with 10101100000153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10101100000153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050550000075 + 5050550000076.
It is an arithmetic number, because the mean of its divisors is an integer number (5050550000076).
Almost surely, 210101100000151 is an apocalyptic number.
10101100000151 is a deficient number, since it is larger than the sum of its proper divisors (1).
10101100000151 is an equidigital number, since it uses as much as digits as its factorization.
10101100000151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5, while the sum is 11.
Adding to 10101100000151 its reverse (15100000110101), we get a palindrome (25201100110252).
The spelling of 10101100000151 in words is "ten trillion, one hundred one billion, one hundred million, one hundred fifty-one", and thus it is an aban number.
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