1010111121401 has 2 divisors, whose sum is σ = 1010111121402. Its totient is φ = 1010111121400.

The previous prime is 1010111121367. The next prime is 1010111121421. The reversal of 1010111121401 is 1041211110101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 617990943376 + 392120178025 = 786124^2 + 626195^2 .

It is an emirp because it is prime and its reverse (1041211110101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1010111121401 - 2¹⁸ = 1010110859257 is a prime.

It is not a weakly prime, because it can be changed into another prime (1010111121421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505055560700 + 505055560701.

It is an arithmetic number, because the mean of its divisors is an integer number (505055560701).

Almost surely, 2^{1010111121401} is an apocalyptic number.

It is an amenable number.

1010111121401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010111121401 is an equidigital number, since it uses as much as digits as its factorization.

1010111121401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 1010111121401 its reverse (1041211110101), we get a palindrome (2051322231502).

The spelling of 1010111121401 in words is "one trillion, ten billion, one hundred eleven million, one hundred twenty-one thousand, four hundred one".