1010111201983 has 8 divisors (see below), whose sum is σ = 1151801008848. Its totient is φ = 877562673024.

The previous prime is 1010111201971. The next prime is 1010111202007. The reversal of 1010111201983 is 3891021110101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1010111201983 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1010111201933) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2285319241 + ... + 2285319682.

It is an arithmetic number, because the mean of its divisors is an integer number (143975126106).

Almost surely, 2^{1010111201983} is an apocalyptic number.

1010111201983 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1010111201983 is a deficient number, since it is larger than the sum of its proper divisors (141689806865).

1010111201983 is a wasteful number, since it uses less digits than its factorization.

1010111201983 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4570638953.

The product of its (nonzero) digits is 432, while the sum is 28.

The spelling of 1010111201983 in words is "one trillion, ten billion, one hundred eleven million, two hundred one thousand, nine hundred eighty-three".