Base | Representation |
---|---|
bin | 11101011001011111010… |
… | …00110110001010010011 |
3 | 10120120021202111110221210 |
4 | 32230233220312022103 |
5 | 113022204314120230 |
6 | 2052012515151203 |
7 | 132656426006514 |
oct | 16545750661223 |
9 | 3516252443853 |
10 | 1010116551315 |
11 | 35a42a506703 |
12 | 143925ba5503 |
13 | 7433b173291 |
14 | 36c65c68a0b |
15 | 1b41e997eb0 |
hex | eb2fa36293 |
1010116551315 has 64 divisors (see below), whose sum is σ = 1655205580800. Its totient is φ = 525832280064.
The previous prime is 1010116551253. The next prime is 1010116551317. The reversal of 1010116551315 is 5131556110101.
It is not a de Polignac number, because 1010116551315 - 215 = 1010116518547 is a prime.
It is a super-3 number, since 3×10101165513153 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1010116551317) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 259734891 + ... + 259738779.
It is an arithmetic number, because the mean of its divisors is an integer number (25862587200).
Almost surely, 21010116551315 is an apocalyptic number.
1010116551315 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1010116551315 is a deficient number, since it is larger than the sum of its proper divisors (645089029485).
1010116551315 is a wasteful number, since it uses less digits than its factorization.
1010116551315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5556.
The product of its (nonzero) digits is 2250, while the sum is 30.
The spelling of 1010116551315 in words is "one trillion, ten billion, one hundred sixteen million, five hundred fifty-one thousand, three hundred fifteen".
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