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10102433111 is a prime number
BaseRepresentation
bin10010110100010011…
…01110010101010111
3222002001111202221022
421122021232111113
5131142210324421
64350242111355
7505230156521
oct113211562527
928061452838
1010102433111
114314618581
121b5b34b55b
13c4cca3594
146bb9c8a11
153e1d937ab
hex25a26e557

10102433111 has 2 divisors, whose sum is σ = 10102433112. Its totient is φ = 10102433110.

The previous prime is 10102433051. The next prime is 10102433123. The reversal of 10102433111 is 11133420101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10102433111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10102433111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10102433611) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5051216555 + 5051216556.

It is an arithmetic number, because the mean of its divisors is an integer number (5051216556).

Almost surely, 210102433111 is an apocalyptic number.

10102433111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10102433111 is an equidigital number, since it uses as much as digits as its factorization.

10102433111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10102433111 its reverse (11133420101), we get a palindrome (21235853212).

The spelling of 10102433111 in words is "ten billion, one hundred two million, four hundred thirty-three thousand, one hundred eleven".