101100011111081 has 2 divisors, whose sum is σ = 101100011111082. Its totient is φ = 101100011111080.

The previous prime is 101100011111051. The next prime is 101100011111083. The reversal of 101100011111081 is 180111110001101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60766842405481 + 40333168705600 = 7795309^2 + 6350840^2 .

It is a cyclic number.

It is not a de Polignac number, because 101100011111081 - 2³⁸ = 100825133204137 is a prime.

It is a super-3 number, since 3×101100011111081³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 101100011111083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (101100011111083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550005555540 + 50550005555541.

It is an arithmetic number, because the mean of its divisors is an integer number (50550005555541).

Almost surely, 2^{101100011111081} is an apocalyptic number.

It is an amenable number.

101100011111081 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100011111081 is an equidigital number, since it uses as much as digits as its factorization.

101100011111081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 17.

Adding to 101100011111081 its reverse (180111110001101), we get a palindrome (281211121112182).

The spelling of 101100011111081 in words is "one hundred one trillion, one hundred billion, eleven million, one hundred eleven thousand, eighty-one".