Base | Representation |
---|---|
bin | 11101011011001000101… |
… | …10110000000001111111 |
3 | 10120122120101202010112211 |
4 | 32231210112300001333 |
5 | 113031012224000223 |
6 | 2052240352041251 |
7 | 133020355465345 |
oct | 16554426600177 |
9 | 3518511663484 |
10 | 1011001000063 |
11 | 35a84378708a |
12 | 143b32233227 |
13 | 7444c483432 |
14 | 36d0b4d7995 |
15 | 1b472451d0d |
hex | eb645b007f |
1011001000063 has 2 divisors, whose sum is σ = 1011001000064. Its totient is φ = 1011001000062.
The previous prime is 1011001000001. The next prime is 1011001000099. The reversal of 1011001000063 is 3600001001101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1011001000063 - 221 = 1010998902911 is a prime.
It is a super-2 number, since 2×10110010000632 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011001000663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505500500031 + 505500500032.
It is an arithmetic number, because the mean of its divisors is an integer number (505500500032).
Almost surely, 21011001000063 is an apocalyptic number.
1011001000063 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011001000063 is an equidigital number, since it uses as much as digits as its factorization.
1011001000063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 1011001000063 its reverse (3600001001101), we get a palindrome (4611002001164).
The spelling of 1011001000063 in words is "one trillion, eleven billion, one million, sixty-three", and thus it is an aban number and an uban number.
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