10110011131111 has 2 divisors, whose sum is σ = 10110011131112. Its totient is φ = 10110011131110.

The previous prime is 10110011131061. The next prime is 10110011131163. The reversal of 10110011131111 is 11113111001101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10110011131111 - 2¹⁹ = 10110010606823 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10110011131091 and 10110011131100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110011131511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055005565555 + 5055005565556.

It is an arithmetic number, because the mean of its divisors is an integer number (5055005565556).

Almost surely, 2^{10110011131111} is an apocalyptic number.

10110011131111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110011131111 is an equidigital number, since it uses as much as digits as its factorization.

10110011131111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 13.

Adding to 10110011131111 its reverse (11113111001101), we get a palindrome (21223122132212).

The spelling of 10110011131111 in words is "ten trillion, one hundred ten billion, eleven million, one hundred thirty-one thousand, one hundred eleven".