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10110012212057 is a prime number
BaseRepresentation
bin1001001100011110101110…
…1011111100001101011001
31022210111201010121122222212
42103013223223330031121
52311120301111241212
633300250412324505
72062265345616362
oct223075353741531
938714633548885
1010110012212057
1132486a536523a
12117347a773735
135844a703caa4
1426d481bb0b69
15127eb814de22
hex931ebafc359

10110012212057 has 2 divisors, whose sum is σ = 10110012212058. Its totient is φ = 10110012212056.

The previous prime is 10110012212009. The next prime is 10110012212059. The reversal of 10110012212057 is 75021221001101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9294059515456 + 815952696601 = 3048616^2 + 903301^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110012212057 - 26 = 10110012211993 is a prime.

Together with 10110012212059, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10110012212059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055006106028 + 5055006106029.

It is an arithmetic number, because the mean of its divisors is an integer number (5055006106029).

Almost surely, 210110012212057 is an apocalyptic number.

It is an amenable number.

10110012212057 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110012212057 is an equidigital number, since it uses as much as digits as its factorization.

10110012212057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 280, while the sum is 23.

Adding to 10110012212057 its reverse (75021221001101), we get a palindrome (85131233213158).

The spelling of 10110012212057 in words is "ten trillion, one hundred ten billion, twelve million, two hundred twelve thousand, fifty-seven".