1011002111983 has 4 divisors (see below), whose sum is σ = 1020450729960. Its totient is φ = 1001553494008.

The previous prime is 1011002111953. The next prime is 1011002112011. The reversal of 1011002111983 is 3891112001101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011002111983 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011002111953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4724308828 + ... + 4724309041.

It is an arithmetic number, because the mean of its divisors is an integer number (255112682490).

Almost surely, 2^{1011002111983} is an apocalyptic number.

1011002111983 is a deficient number, since it is larger than the sum of its proper divisors (9448617977).

1011002111983 is an equidigital number, since it uses as much as digits as its factorization.

1011002111983 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9448617976.

The product of its (nonzero) digits is 432, while the sum is 28.

The spelling of 1011002111983 in words is "one trillion, eleven billion, two million, one hundred eleven thousand, nine hundred eighty-three".