1011002112011 has 2 divisors, whose sum is σ = 1011002112012. Its totient is φ = 1011002112010.

The previous prime is 1011002111953. The next prime is 1011002112013. The reversal of 1011002112011 is 1102112001101.

It is a strong prime.

It is an emirp because it is prime and its reverse (1102112001101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011002112011 is a prime.

Together with 1011002112013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1011002111983 and 1011002112001.

It is not a weakly prime, because it can be changed into another prime (1011002112013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505501056005 + 505501056006.

It is an arithmetic number, because the mean of its divisors is an integer number (505501056006).

Almost surely, 2^{1011002112011} is an apocalyptic number.

1011002112011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011002112011 is an equidigital number, since it uses as much as digits as its factorization.

1011002112011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 1011002112011 its reverse (1102112001101), we get a palindrome (2113114113112).

The spelling of 1011002112011 in words is "one trillion, eleven billion, two million, one hundred twelve thousand, eleven".