101100311401 has 2 divisors, whose sum is σ = 101100311402. Its totient is φ = 101100311400.

The previous prime is 101100311327. The next prime is 101100311407. The reversal of 101100311401 is 104113001101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67859729001 + 33240582400 = 260499^2 + 182320^2 .

It is an emirp because it is prime and its reverse (104113001101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101100311401 - 2¹¹ = 101100309353 is a prime.

It is not a weakly prime, because it can be changed into another prime (101100311407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550155700 + 50550155701.

It is an arithmetic number, because the mean of its divisors is an integer number (50550155701).

Almost surely, 2^101100311401 is an apocalyptic number.

It is an amenable number.

101100311401 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100311401 is an equidigital number, since it uses as much as digits as its factorization.

101100311401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 101100311401 its reverse (104113001101), we get a palindrome (205213312502).

The spelling of 101100311401 in words is "one hundred one billion, one hundred million, three hundred eleven thousand, four hundred one".