Base | Representation |
---|---|
bin | 10110111111001101000000… |
… | …010011011000011100000111 |
3 | 111020222002120201020022102212 |
4 | 112333031000103120130013 |
5 | 101222411420341100312 |
6 | 555004502034254035 |
7 | 30203154012641111 |
oct | 2677150023303407 |
9 | 436862521208385 |
10 | 101100314003207 |
11 | 2a239447636452 |
12 | b409b0272731b |
13 | 4454945cb2a1c |
14 | 1ad73d1c963b1 |
15 | ba4cb7ae8822 |
hex | 5bf3404d8707 |
101100314003207 has 2 divisors, whose sum is σ = 101100314003208. Its totient is φ = 101100314003206.
The previous prime is 101100314003189. The next prime is 101100314003239. The reversal of 101100314003207 is 702300413001101.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101100314003207 - 210 = 101100314002183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101100314023207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550157001603 + 50550157001604.
It is an arithmetic number, because the mean of its divisors is an integer number (50550157001604).
Almost surely, 2101100314003207 is an apocalyptic number.
101100314003207 is a deficient number, since it is larger than the sum of its proper divisors (1).
101100314003207 is an equidigital number, since it uses as much as digits as its factorization.
101100314003207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 101100314003207 its reverse (702300413001101), we get a palindrome (803400727004308).
The spelling of 101100314003207 in words is "one hundred one trillion, one hundred billion, three hundred fourteen million, three thousand, two hundred seven".
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