101101000000597 has 2 divisors, whose sum is σ = 101101000000598. Its totient is φ = 101101000000596.

The previous prime is 101101000000579. The next prime is 101101000000633. The reversal of 101101000000597 is 795000000101101.

Together with previous prime (101101000000579) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101100330277956 + 669722641 = 10054866^2 + 25879^2 .

It is a cyclic number.

It is not a de Polignac number, because 101101000000597 - 2¹¹ = 101100999998549 is a prime.

It is a super-2 number, since 2×101101000000597² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101101000000997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550500000298 + 50550500000299.

It is an arithmetic number, because the mean of its divisors is an integer number (50550500000299).

Almost surely, 2^{101101000000597} is an apocalyptic number.

It is an amenable number.

101101000000597 is a deficient number, since it is larger than the sum of its proper divisors (1).

101101000000597 is an equidigital number, since it uses as much as digits as its factorization.

101101000000597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 315, while the sum is 25.

Adding to 101101000000597 its reverse (795000000101101), we get a palindrome (896101000101698).

The spelling of 101101000000597 in words is "one hundred one trillion, one hundred one billion, five hundred ninety-seven", and thus it is an aban number.