Base | Representation |
---|---|
bin | 101111000101000010… |
… | …1101101100110110111 |
3 | 100122221220100222212211 |
4 | 1132022011231212313 |
5 | 3124023324014033 |
6 | 114240053154251 |
7 | 10206243221242 |
oct | 1361205554667 |
9 | 318856328784 |
10 | 101101001143 |
11 | 399709745aa |
12 | 1771662b987 |
13 | 96c2950ccc |
14 | 4c71380259 |
15 | 296ac1c2cd |
hex | 178a16d9b7 |
101101001143 has 2 divisors, whose sum is σ = 101101001144. Its totient is φ = 101101001142.
The previous prime is 101101001107. The next prime is 101101001147. The reversal of 101101001143 is 341100101101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101101001143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101101001147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550500571 + 50550500572.
It is an arithmetic number, because the mean of its divisors is an integer number (50550500572).
Almost surely, 2101101001143 is an apocalyptic number.
101101001143 is a deficient number, since it is larger than the sum of its proper divisors (1).
101101001143 is an equidigital number, since it uses as much as digits as its factorization.
101101001143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 101101001143 its reverse (341100101101), we get a palindrome (442201102244).
The spelling of 101101001143 in words is "one hundred one billion, one hundred one million, one thousand, one hundred forty-three".
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