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101103113310 = 23519595415557
BaseRepresentation
bin101111000101000110…
…1110001010001011110
3100122222001100022020020
41132022031301101132
53124024344111220
6114240210333010
710206300166203
oct1361215612136
9318861308206
10101103113310
11399720874a1
121771728a166
1396c3210504
144c7176dcaa
15296aed8040
hex178a37145e

101103113310 has 128 divisors (see below), whose sum is σ = 260274470400. Its totient is φ = 25058004480.

The previous prime is 101103113249. The next prime is 101103113323. The reversal of 101103113310 is 13311301101.

It is a super-2 number, since 2×1011031133102 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 101103113310.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 18191052 + ... + 18196608.

It is an arithmetic number, because the mean of its divisors is an integer number (2033394300).

Almost surely, 2101103113310 is an apocalyptic number.

101103113310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 101103113310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (130137235200).

101103113310 is an abundant number, since it is smaller than the sum of its proper divisors (159171357090).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101103113310 is a wasteful number, since it uses less digits than its factorization.

101103113310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6186.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 101103113310 its reverse (13311301101), we get a palindrome (114414414411).

The spelling of 101103113310 in words is "one hundred one billion, one hundred three million, one hundred thirteen thousand, three hundred ten".

Divisors: 1 2 3 5 6 10 15 19 30 38 57 59 95 114 118 177 190 285 295 354 541 570 590 885 1082 1121 1623 1770 2242 2705 3246 3363 5410 5557 5605 6726 8115 10279 11114 11210 16230 16671 16815 20558 27785 30837 31919 33342 33630 51395 55570 61674 63838 83355 95757 102790 105583 154185 159595 166710 191514 211166 308370 316749 319190 327863 478785 527915 606461 633498 655726 957570 983589 1055830 1212922 1583745 1639315 1819383 1967178 3006337 3032305 3167490 3278630 3638766 4917945 6012674 6064610 6229397 9019011 9096915 9835890 12458794 15031685 18038022 18193830 18688191 30063370 31146985 37376382 45095055 57120403 62293970 90190110 93440955 114240806 171361209 177373883 186881910 285602015 342722418 354747766 532121649 571204030 856806045 886869415 1064243298 1713612090 1773738830 2660608245 3370103777 5321216490 6740207554 10110311331 16850518885 20220622662 33701037770 50551556655 101103113310