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10110313519 is a prime number
BaseRepresentation
bin10010110101001111…
…10010010000101111
3222002121100010211021
421122213302100233
5131201220013034
64351123035011
7505354150465
oct113247622057
928077303737
1010110313519
114319010209
121b61b0ba67
13c51802447
146bca7a835
153e28ed6b4
hex25a9f242f

10110313519 has 2 divisors, whose sum is σ = 10110313520. Its totient is φ = 10110313518.

The previous prime is 10110313511. The next prime is 10110313523. The reversal of 10110313519 is 91531301101.

It is a happy number.

10110313519 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10110313519 - 23 = 10110313511 is a prime.

It is a super-2 number, since 2×101103135192 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10110313493 and 10110313502.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110313511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055156759 + 5055156760.

It is an arithmetic number, because the mean of its divisors is an integer number (5055156760).

Almost surely, 210110313519 is an apocalyptic number.

10110313519 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110313519 is an equidigital number, since it uses as much as digits as its factorization.

10110313519 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 405, while the sum is 25.

The spelling of 10110313519 in words is "ten billion, one hundred ten million, three hundred thirteen thousand, five hundred nineteen".