Base | Representation |
---|---|
bin | 11101011011010100100… |
… | …00110010111001000101 |
3 | 10120122211022020001010211 |
4 | 32231222100302321011 |
5 | 113031213111232323 |
6 | 2052254252115421 |
7 | 133023001031035 |
oct | 16555220627105 |
9 | 3518738201124 |
10 | 1011100102213 |
11 | 35a894714a93 |
12 | 143b5b465b71 |
13 | 74466b71366 |
14 | 36d1a7338c5 |
15 | 1b47aeca70d |
hex | eb6a432e45 |
1011100102213 has 4 divisors (see below), whose sum is σ = 1011109554208. Its totient is φ = 1011090650220.
The previous prime is 1011100102211. The next prime is 1011100102219. The reversal of 1011100102213 is 3122010011101.
It is a happy number.
1011100102213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1011100102213 - 21 = 1011100102211 is a prime.
It is a super-3 number, since 3×10111001022133 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1011100102193 and 1011100102202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1011100102211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4563681 + ... + 4780102.
It is an arithmetic number, because the mean of its divisors is an integer number (252777388552).
Almost surely, 21011100102213 is an apocalyptic number.
It is an amenable number.
1011100102213 is a deficient number, since it is larger than the sum of its proper divisors (9451995).
1011100102213 is an equidigital number, since it uses as much as digits as its factorization.
1011100102213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9451994.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 1011100102213 its reverse (3122010011101), we get a palindrome (4133110113314).
The spelling of 1011100102213 in words is "one trillion, eleven billion, one hundred million, one hundred two thousand, two hundred thirteen".
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