10111012141 has 2 divisors, whose sum is σ = 10111012142. Its totient is φ = 10111012140.

The previous prime is 10111012097. The next prime is 10111012159. The reversal of 10111012141 is 14121011101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5273809641 + 4837202500 = 72621^2 + 69550^2 .

It is a cyclic number.

It is not a de Polignac number, because 10111012141 - 2¹¹ = 10111010093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10111012181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055506070 + 5055506071.

It is an arithmetic number, because the mean of its divisors is an integer number (5055506071).

Almost surely, 2^10111012141 is an apocalyptic number.

It is an amenable number.

10111012141 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111012141 is an equidigital number, since it uses as much as digits as its factorization.

10111012141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 10111012141 its reverse (14121011101), we get a palindrome (24232023242).

The spelling of 10111012141 in words is "ten billion, one hundred eleven million, twelve thousand, one hundred forty-one".