1011102102013 has 2 divisors, whose sum is σ = 1011102102014. Its totient is φ = 1011102102012.

The previous prime is 1011102101963. The next prime is 1011102102077. The reversal of 1011102102013 is 3102012011101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 941214306244 + 69887795769 = 970162^2 + 264363^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011102102013 - 2²⁵ = 1011068547581 is a prime.

It is a super-3 number, since 3×1011102102013³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011102101984 and 1011102102002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011102172013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505551051006 + 505551051007.

It is an arithmetic number, because the mean of its divisors is an integer number (505551051007).

Almost surely, 2^{1011102102013} is an apocalyptic number.

It is an amenable number.

1011102102013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011102102013 is an equidigital number, since it uses as much as digits as its factorization.

1011102102013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1011102102013 its reverse (3102012011101), we get a palindrome (4113114113114).

The spelling of 1011102102013 in words is "one trillion, eleven billion, one hundred two million, one hundred two thousand, thirteen".