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1011102102022 = 2505551051011
BaseRepresentation
bin11101011011010100110…
…00011011001000000110
310120122211102222122100211
432231222120123020012
5113031214114231042
62052254403030034
7133023024030265
oct16555230331006
93518742878324
101011102102022
1135a895860521
12143b6006b31a
13744673c168c
1436d1aad45dc
151b47b273017
hexeb6a61b206

1011102102022 has 4 divisors (see below), whose sum is σ = 1516653153036. Its totient is φ = 505551051010.

The previous prime is 1011102102013. The next prime is 1011102102077. The reversal of 1011102102022 is 2202012011101.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×10111021020223 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011102101993 and 1011102102011.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252775525504 + ... + 252775525507.

It is an arithmetic number, because the mean of its divisors is an integer number (379163288259).

Almost surely, 21011102102022 is an apocalyptic number.

1011102102022 is a deficient number, since it is larger than the sum of its proper divisors (505551051014).

1011102102022 is an equidigital number, since it uses as much as digits as its factorization.

1011102102022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 505551051013.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 1011102102022 its reverse (2202012011101), we get a palindrome (3213114113123).

The spelling of 1011102102022 in words is "one trillion, eleven billion, one hundred two million, one hundred two thousand, twenty-two".

Divisors: 1 2 505551051011 1011102102022