1011102313301 has 4 divisors (see below), whose sum is σ = 1026193392672. Its totient is φ = 996011233932.

The previous prime is 1011102313229. The next prime is 1011102313327. The reversal of 1011102313301 is 1033132011101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011102313301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1011102313301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011102313901) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7545539585 + ... + 7545539718.

It is an arithmetic number, because the mean of its divisors is an integer number (256548348168).

Almost surely, 2^{1011102313301} is an apocalyptic number.

It is an amenable number.

1011102313301 is a deficient number, since it is larger than the sum of its proper divisors (15091079371).

1011102313301 is an equidigital number, since it uses as much as digits as its factorization.

1011102313301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15091079370.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1011102313301 its reverse (1033132011101), we get a palindrome (2044234324402).

The spelling of 1011102313301 in words is "one trillion, eleven billion, one hundred two million, three hundred thirteen thousand, three hundred one".