10111041011 has 2 divisors, whose sum is σ = 10111041012. Its totient is φ = 10111041010.

The previous prime is 10111040999. The next prime is 10111041047. The reversal of 10111041011 is 11014011101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10111041011 is a prime.

It is a super-2 number, since 2×10111041011² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10111040983 and 10111041001.

It is not a weakly prime, because it can be changed into another prime (10111041071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055520505 + 5055520506.

It is an arithmetic number, because the mean of its divisors is an integer number (5055520506).

Almost surely, 2^10111041011 is an apocalyptic number.

10111041011 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111041011 is an equidigital number, since it uses as much as digits as its factorization.

10111041011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 10111041011 its reverse (11014011101), we get a palindrome (21125052112).

The spelling of 10111041011 in words is "ten billion, one hundred eleven million, forty-one thousand, eleven".