101111110099471 has 2 divisors, whose sum is σ = 101111110099472. Its totient is φ = 101111110099470.

The previous prime is 101111110099469. The next prime is 101111110099513. The reversal of 101111110099471 is 174990011111101.

It is a weak prime.

It is an emirp because it is prime and its reverse (174990011111101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101111110099471 - 2¹ = 101111110099469 is a prime.

It is a super-3 number, since 3×101111110099471³ (a number of 43 digits) contains 333 as substring.

Together with 101111110099469, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 101111110099471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101111110099421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555555049735 + 50555555049736.

It is an arithmetic number, because the mean of its divisors is an integer number (50555555049736).

Almost surely, 2^{101111110099471} is an apocalyptic number.

101111110099471 is a deficient number, since it is larger than the sum of its proper divisors (1).

101111110099471 is an equidigital number, since it uses as much as digits as its factorization.

101111110099471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2268, while the sum is 37.

The spelling of 101111110099471 in words is "one hundred one trillion, one hundred eleven billion, one hundred ten million, ninety-nine thousand, four hundred seventy-one".