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10111112002127 is a prime number
BaseRepresentation
bin1001001100100010110100…
…1111010011101001001111
31022210121112210001210100102
42103020231033103221033
52311130024133032002
633300551500521315
72062334531646413
oct223105517235117
938717483053312
1010111112002127
11324910a146854
121173726b5023b
13584620b49046
1426d547c96d43
1512802e992a02
hex9322d3d3a4f

10111112002127 has 2 divisors, whose sum is σ = 10111112002128. Its totient is φ = 10111112002126.

The previous prime is 10111112002091. The next prime is 10111112002133. The reversal of 10111112002127 is 72120021111101.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10111112002127 - 210 = 10111112001103 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10111112002099 and 10111112002108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10111112002157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055556001063 + 5055556001064.

It is an arithmetic number, because the mean of its divisors is an integer number (5055556001064).

Almost surely, 210111112002127 is an apocalyptic number.

10111112002127 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111112002127 is an equidigital number, since it uses as much as digits as its factorization.

10111112002127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 20.

Adding to 10111112002127 its reverse (72120021111101), we get a palindrome (82231133113228).

The spelling of 10111112002127 in words is "ten trillion, one hundred eleven billion, one hundred twelve million, two thousand, one hundred twenty-seven".