Base | Representation |
---|---|
bin | 10110111111011000000110… |
… | …100111111101111111100111 |
3 | 111021000020100020120211001202 |
4 | 112333120012213331333213 |
5 | 101223110322143121041 |
6 | 555014152345513115 |
7 | 30204055230432662 |
oct | 2677300647757747 |
9 | 437006306524052 |
10 | 101112231223271 |
11 | 2a243502598254 |
12 | b4102897a279b |
13 | 4455ac4c52a28 |
14 | 1ad7c028c66d9 |
15 | ba5263e66a9b |
hex | 5bf6069fdfe7 |
101112231223271 has 2 divisors, whose sum is σ = 101112231223272. Its totient is φ = 101112231223270.
The previous prime is 101112231223243. The next prime is 101112231223273. The reversal of 101112231223271 is 172322132211101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101112231223271 - 238 = 100837353316327 is a prime.
Together with 101112231223273, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101112231223273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556115611635 + 50556115611636.
It is an arithmetic number, because the mean of its divisors is an integer number (50556115611636).
Almost surely, 2101112231223271 is an apocalyptic number.
101112231223271 is a deficient number, since it is larger than the sum of its proper divisors (1).
101112231223271 is an equidigital number, since it uses as much as digits as its factorization.
101112231223271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 29.
Adding to 101112231223271 its reverse (172322132211101), we get a palindrome (273434363434372).
The spelling of 101112231223271 in words is "one hundred one trillion, one hundred twelve billion, two hundred thirty-one million, two hundred twenty-three thousand, two hundred seventy-one".
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