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10111223133 = 3211102133567
BaseRepresentation
bin10010110101010110…
…10000010101011101
3222002200001100120200
421122223100111131
5131201433120013
64351154334113
7505364656434
oct113253202535
928080040520
1010111223133
114319581660
121b6228a339
13c51a6048b
146bcc3611b
153e2a2ce73
hex25aad055d

10111223133 has 12 divisors (see below), whose sum is σ = 15932836608. Its totient is φ = 6128013960.

The previous prime is 10111223119. The next prime is 10111223167. The reversal of 10111223133 is 33132211101.

10111223133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10111223133 - 233 = 1521288541 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10111223113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 51066685 + ... + 51066882.

It is an arithmetic number, because the mean of its divisors is an integer number (1327736384).

Almost surely, 210111223133 is an apocalyptic number.

It is an amenable number.

10111223133 is a deficient number, since it is larger than the sum of its proper divisors (5821613475).

10111223133 is a wasteful number, since it uses less digits than its factorization.

10111223133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102133584 (or 102133581 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 10111223133 its reverse (33132211101), we get a palindrome (43243434234).

The spelling of 10111223133 in words is "ten billion, one hundred eleven million, two hundred twenty-three thousand, one hundred thirty-three".

Divisors: 1 3 9 11 33 99 102133567 306400701 919202103 1123469237 3370407711 10111223133