Base | Representation |
---|---|
bin | 11101011011011000001… |
… | …11001010110100100111 |
3 | 10120122220110121120200111 |
4 | 32231230013022310213 |
5 | 113031244032230343 |
6 | 2052301321153451 |
7 | 133023525552331 |
oct | 16555407126447 |
9 | 3518813546614 |
10 | 1011131133223 |
11 | 35a90018a052 |
12 | 143b6992b887 |
13 | 744704176c3 |
14 | 36d208d0451 |
15 | 1b47daa9c9d |
hex | eb6c1cad27 |
1011131133223 has 4 divisors (see below), whose sum is σ = 1013652657648. Its totient is φ = 1008609608800.
The previous prime is 1011131133169. The next prime is 1011131133281. The reversal of 1011131133223 is 3223311311101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1011131133223 - 213 = 1011131125031 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1011131133194 and 1011131133203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1011131133923) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1260761611 + ... + 1260762412.
It is an arithmetic number, because the mean of its divisors is an integer number (253413164412).
Almost surely, 21011131133223 is an apocalyptic number.
1011131133223 is a deficient number, since it is larger than the sum of its proper divisors (2521524425).
1011131133223 is an equidigital number, since it uses as much as digits as its factorization.
1011131133223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2521524424.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 1011131133223 its reverse (3223311311101), we get a palindrome (4234442444324).
The spelling of 1011131133223 in words is "one trillion, eleven billion, one hundred thirty-one million, one hundred thirty-three thousand, two hundred twenty-three".
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