Base | Representation |
---|---|
bin | 10010110101010111… |
… | …00101111010111001 |
3 | 222002200012211212012 |
4 | 21122223211322321 |
5 | 131201443432140 |
6 | 4351200255305 |
7 | 505365505256 |
oct | 113253457271 |
9 | 28080184765 |
10 | 10111311545 |
11 | 4319632025 |
12 | 1b62311535 |
13 | c51a917aa |
14 | 6bcc5a42d |
15 | 3e2a49265 |
hex | 25aae5eb9 |
10111311545 has 4 divisors (see below), whose sum is σ = 12133573860. Its totient is φ = 8089049232.
The previous prime is 10111311517. The next prime is 10111311559. The reversal of 10111311545 is 54511311101.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54511311101 = 13 ⋅4193177777.
It can be written as a sum of positive squares in 2 ways, for example, as 3565045264 + 6546266281 = 59708^2 + 80909^2 .
It is a cyclic number.
It is not a de Polignac number, because 10111311545 - 226 = 10044202681 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10111311545.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1011131150 + ... + 1011131159.
It is an arithmetic number, because the mean of its divisors is an integer number (3033393465).
Almost surely, 210111311545 is an apocalyptic number.
It is an amenable number.
10111311545 is a deficient number, since it is larger than the sum of its proper divisors (2022262315).
10111311545 is an equidigital number, since it uses as much as digits as its factorization.
10111311545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2022262314.
The product of its (nonzero) digits is 300, while the sum is 23.
Adding to 10111311545 its reverse (54511311101), we get a palindrome (64622622646).
The spelling of 10111311545 in words is "ten billion, one hundred eleven million, three hundred eleven thousand, five hundred forty-five".
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