10111313231 has 4 divisors (see below), whose sum is σ = 10130721264. Its totient is φ = 10091905200.

The previous prime is 10111313209. The next prime is 10111313237. The reversal of 10111313231 is 13231311101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13231311101 = 73 ⋅181250837.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10111313231 is a prime.

It is a super-2 number, since 2×10111313231² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10111313237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9703235 + ... + 9704276.

It is an arithmetic number, because the mean of its divisors is an integer number (2532680316).

Almost surely, 2^10111313231 is an apocalyptic number.

10111313231 is a deficient number, since it is larger than the sum of its proper divisors (19408033).

10111313231 is an equidigital number, since it uses as much as digits as its factorization.

10111313231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19408032.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10111313231 its reverse (13231311101), we get a palindrome (23342624332).

The spelling of 10111313231 in words is "ten billion, one hundred eleven million, three hundred thirteen thousand, two hundred thirty-one".