101113144125 has 64 divisors (see below), whose sum is σ = 192724586496. Its totient is φ = 46118280000.

The previous prime is 101113144117. The next prime is 101113144159. The reversal of 101113144125 is 521441311101.

It is not a de Polignac number, because 101113144125 - 2³ = 101113144117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101113144095 and 101113144104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1119400 + ... + 1206350.

It is an arithmetic number, because the mean of its divisors is an integer number (3011321664).

Almost surely, 2^101113144125 is an apocalyptic number.

101113144125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

101113144125 is a deficient number, since it is larger than the sum of its proper divisors (91611442371).

101113144125 is an equidigital number, since it uses as much as digits as its factorization.

101113144125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87419 (or 87409 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 24.

Adding to 101113144125 its reverse (521441311101), we get a palindrome (622554455226).

The spelling of 101113144125 in words is "one hundred one billion, one hundred thirteen million, one hundred forty-four thousand, one hundred twenty-five".