Base | Representation |
---|---|
bin | 11101011011100000011… |
… | …01111000100001000000 |
3 | 10120200002021012111001002 |
4 | 32231300031320201000 |
5 | 113031414200031422 |
6 | 2052312221231132 |
7 | 133025323125266 |
oct | 16556015704100 |
9 | 3520067174032 |
10 | 1011200002112 |
11 | 35a936048293 |
12 | 143b88a024a8 |
13 | 7448177b421 |
14 | 36d29ada436 |
15 | 1b484b60692 |
hex | eb70378840 |
1011200002112 has 14 divisors (see below), whose sum is σ = 2006600004318. Its totient is φ = 505600001024.
The previous prime is 1011200002097. The next prime is 1011200002157. The reversal of 1011200002112 is 2112000021101.
It can be written as a sum of positive squares in only one way, i.e., 1005896667136 + 5303334976 = 1002944^2 + 72824^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1011200002093 and 1011200002102.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7899999953 + ... + 7900000080.
It is an arithmetic number, because the mean of its divisors is an integer number (143328571737).
Almost surely, 21011200002112 is an apocalyptic number.
It is an amenable number.
1011200002112 is a deficient number, since it is larger than the sum of its proper divisors (995400002206).
1011200002112 is an equidigital number, since it uses as much as digits as its factorization.
1011200002112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15800000045 (or 15800000035 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 1011200002112 its reverse (2112000021101), we get a palindrome (3123200023213).
The spelling of 1011200002112 in words is "one trillion, eleven billion, two hundred million, two thousand, one hundred twelve".
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