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101120001014111 is a prime number
BaseRepresentation
bin10110111111011111010101…
…101111010111100101011111
3111021000222101201211002100212
4112333133111233113211133
5101223222230224422421
6555021515343243035
730204451614526262
oct2677372557274537
9437028351732325
10101120001014111
112a24682a41a0a2
12b4118978a947b
1344567628925c1
141ad833c786cd9
15ba556b13be5b
hex5bf7d5bd795f

101120001014111 has 2 divisors, whose sum is σ = 101120001014112. Its totient is φ = 101120001014110.

The previous prime is 101120001014069. The next prime is 101120001014147. The reversal of 101120001014111 is 111410100021101.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101120001014111 - 26 = 101120001014047 is a prime.

It is a super-2 number, since 2×1011200010141112 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101120001614111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560000507055 + 50560000507056.

It is an arithmetic number, because the mean of its divisors is an integer number (50560000507056).

Almost surely, 2101120001014111 is an apocalyptic number.

101120001014111 is a deficient number, since it is larger than the sum of its proper divisors (1).

101120001014111 is an equidigital number, since it uses as much as digits as its factorization.

101120001014111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 101120001014111 its reverse (111410100021101), we get a palindrome (212530101035212).

The spelling of 101120001014111 in words is "one hundred one trillion, one hundred twenty billion, one million, fourteen thousand, one hundred eleven".