Base | Representation |
---|---|
bin | 101111000101100111… |
… | …0010001101001000111 |
3 | 100200000020011102010011 |
4 | 1132023032101221013 |
5 | 3124043211214421 |
6 | 114242013011051 |
7 | 10206564005002 |
oct | 1361316215107 |
9 | 320006142104 |
10 | 101120023111 |
11 | 39980687038 |
12 | 17720a83a87 |
13 | 96c6881203 |
14 | 4c73ad2539 |
15 | 296c7284e1 |
hex | 178b391a47 |
101120023111 has 2 divisors, whose sum is σ = 101120023112. Its totient is φ = 101120023110.
The previous prime is 101120023087. The next prime is 101120023153. The reversal of 101120023111 is 111320021101.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101120023111 - 215 = 101119990343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101120023091 and 101120023100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101120023811) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560011555 + 50560011556.
It is an arithmetic number, because the mean of its divisors is an integer number (50560011556).
Almost surely, 2101120023111 is an apocalyptic number.
101120023111 is a deficient number, since it is larger than the sum of its proper divisors (1).
101120023111 is an equidigital number, since it uses as much as digits as its factorization.
101120023111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 101120023111 its reverse (111320021101), we get a palindrome (212440044212).
The spelling of 101120023111 in words is "one hundred one billion, one hundred twenty million, twenty-three thousand, one hundred eleven".
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