1011201012013 has 2 divisors, whose sum is σ = 1011201012014. Its totient is φ = 1011201012012.

The previous prime is 1011201011987. The next prime is 1011201012023. The reversal of 1011201012013 is 3102101021101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1003517087049 + 7683924964 = 1001757^2 + 87658^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011201012013 - 2²⁵ = 1011167457581 is a prime.

It is a super-2 number, since 2×1011201012013² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011201011984 and 1011201012002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011201012023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505600506006 + 505600506007.

It is an arithmetic number, because the mean of its divisors is an integer number (505600506007).

Almost surely, 2^{1011201012013} is an apocalyptic number.

It is an amenable number.

1011201012013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011201012013 is an equidigital number, since it uses as much as digits as its factorization.

1011201012013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1011201012013 its reverse (3102101021101), we get a palindrome (4113302033114).

The spelling of 1011201012013 in words is "one trillion, eleven billion, two hundred one million, twelve thousand, thirteen".