10112020213 has 2 divisors, whose sum is σ = 10112020214. Its totient is φ = 10112020212.

The previous prime is 10112020211. The next prime is 10112020241. The reversal of 10112020213 is 31202021101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9940488804 + 171531409 = 99702^2 + 13097^2 .

It is a cyclic number.

It is not a de Polignac number, because 10112020213 - 2¹ = 10112020211 is a prime.

Together with 10112020211, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10112020193 and 10112020202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112020211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056010106 + 5056010107.

It is an arithmetic number, because the mean of its divisors is an integer number (5056010107).

Almost surely, 2^10112020213 is an apocalyptic number.

It is an amenable number.

10112020213 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112020213 is an equidigital number, since it uses as much as digits as its factorization.

10112020213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10112020213 its reverse (31202021101), we get a palindrome (41314041314).

The spelling of 10112020213 in words is "ten billion, one hundred twelve million, twenty thousand, two hundred thirteen".